Chapter 6: Q 90 (page 589)

In the following exercises, factor completely using trial and error.
$q^{3} - 5 q^{2} - 24 q$

Short Answer

Expert verified

The factorization of the expression is

$q^{3} - 5 q^{2} - 24 q = q (q - 8) (q + 3)$

Step by step solution

Step 1. Given Information

Consider the expression $q^{3} - 5 q^{2} - 24 q$

The objective is to factor the expression completely by using the trial and error method.

Step 2. Factor out the GCF

The GCF of the three terms in the expression is $q$ . So factor the GCF from the expression we get

role="math" localid="1644592611728" $\begin{array}{rcl} q^{3} - 5 q^{2} - 24 q & = & q \cdot q^{2} - q \cdot 5 q - q \cdot 24 \\ = & q (q^{2} - 5 q - 24) \end{array}$

Step 3. Factor using trial and error

The factors of the first term and the last term of the trinomial $\begin{array}{rcl} q^{2} - 5 q - 24 \end{array}$ are

$q^{2} = q \cdot q - 24 = - 2 \cdot 12 o r - 3 \cdot 8 o r - 4 \cdot 6$

Consider all the combinations of factors

$q^{2} - 5 q - 24$
Possible Factors	Product
$(q - 2) (q + 12)$	$q^{2} + 12 q - 2 q - 24 = q^{2} + 10 q - 24$
$(q + 2) (q - 12)$	$q^{2} - 12 q + 2 q - 24 = q^{2} - 10 q - 24$
$(q - 3) (q + 8)$	$q^{2} + 8 q - 3 q - 24 = q^{2} + 5 q - 24$
$(q + 3) (q - 8)$	$q^{2} - 8 q + 3 q - 24 = q^{2} - 5 q - 24$
$(q + 4) (q - 6)$	$q^{2} - 6 q + 4 q - 24 = q^{2} - 2 q - 24$
$(q - 4) (q + 6)$	$q^{2} + 6 q - 4 q - 24 = q^{2} + 2 q - 24$

So the correct factors are $(q + 3) (q - 8)$

Thus, $q^{3} - 5 q^{2} - 24 q = q (q + 3) (q - 8)$

Step 4. Check the factors

Multiply the factors to check the solution

$\begin{array}{rcl} q (q + 3) (q - 8) & = & q (q^{2} - 8 q + 3 q - 24) \\ = & q (q^{2} - 5 q - 24) \\ = & q^{3} - 5 q^{2} - 24 q \end{array}$

And we get the given expression. So the expression is correctly factored.

Unlock Step-by-Step Solutions & Ace Your Exams!

Full Textbook Solutions
Get detailed explanations and key concepts
Unlimited Al creation
Al flashcards, explanations, exams and more...
Ads-free access
To over 500 millions flashcards
Money-back guarantee
We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

In the following exercises, factor completely using trial and error.
$q^{3} - 5 q^{2} - 24 q$

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Factor out the GCF

Step 3. Factor using trial and error

Step 4. Check the factors

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Discrete Mathematics

Geometry

Mechanics Maths

Statistics

Logic and Functions

Probability and Statistics

Study anywhere. Anytime. Across all devices.

In the following exercises, factor completely using trial and error.q3-5q2-24q

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Factor out the GCF

Step 3. Factor using trial and error

Step 4. Check the factors

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Discrete Mathematics

Geometry

Mechanics Maths

Statistics

Logic and Functions

Probability and Statistics

Study anywhere. Anytime. Across all devices.

In the following exercises, factor completely using trial and error.
$q^{3} - 5 q^{2} - 24 q$