Chapter 1: Q 121. (page 39)

In the following exercises, evaluate each expression.
${(x + y)}^{2}$ when $x = - 3$ and $y = 14$

Short Answer

Expert verified

The value is 121.

Step by step solution

Step 1. Given Information:

The given expression is ${(x + y)}^{2}$ and the value of the variables are $x = - 3$ and $y = 14$ .

Step 2. Substitute the values:

Substitute $- 3$ for $x$ and 14 for $y$ into the given expression ${(x + y)}^{2}$ .

${((- 3) + 14)}^{2}$

Step 3. Perform Addition:

Add $- 3$ and 14 inside the parentheses.

${((- 3) + 14)}^{2} = {(11)}^{2}$

Step 4. Calculate the exponent:

Calculate the exponent using the definition of exponential notation, $a^{n} = \underset{n f a c t o r s}{\underset{⏟}{a \cdot a \cdot \dots \cdot a}}$ .

$\begin{array}{rcl} {(11)}^{2} & = & 11 \cdot 11 \\ = & 121 \end{array}$

Step 5. Conclusion:

The value is 121.

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In the following exercises, evaluate each expression.
${(x + y)}^{2}$ when $x = - 3$ and $y = 14$

Short Answer

Step by step solution

Step 1. Given Information:

Step 2. Substitute the values:

Step 3. Perform Addition:

Step 4. Calculate the exponent:

Step 5. Conclusion:

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In the following exercises, evaluate each expression. x+y2whenx=-3andy=14

Short Answer

Step by step solution

Step 1. Given Information:

Step 2. Substitute the values:

Step 3. Perform Addition:

Step 4. Calculate the exponent:

Step 5. Conclusion:

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Logic and Functions

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Study anywhere. Anytime. Across all devices.

In the following exercises, evaluate each expression.
${(x + y)}^{2}$ when $x = - 3$ and $y = 14$