Chapter 1: Q 1.41. (page 34)

Evaluate: $3 x^{2} - 2 x y + 6 y^{2}$ when $x = 1, y = - 2$ .

Short Answer

Expert verified

The value is 31.

Step by step solution

Step 1. Given Information:

The given expression is $3 x^{2} - 2 x y + 6 y^{2}$ and the values of the variables are $x = 1$ and $y = - 2$ .

Step 2. Substitute the values:

Substitute 1 for $x$ and $- 2$ for $y$ into the given expression $3 x^{2} - 2 x y + 6 y^{2}$ .

$3 {(1)}^{2} - 2 (1) (- 2) + 6 {(- 2)}^{2}$

Step 3. Calculate the exponents:

The value of the exponents are ${(1)}^{2} = 1$ and ${(- 2)}^{2} = 4$ . Simplify the exponents in the obtained expression.

$3 \cdot 1 - 2 (1) (- 2) + 6 \cdot 4$

Step 4. Multiply:

Perform multiplication from left to right.

$3 - (- 4) + 24$

Step 5. Perform Subtraction:

Subtract $- 4$ from 3 in the obtained expression.

$7 + 24$

Step 6. Perform Addition:

Add 7 and 24 in the obtained expression.

$7 + 24 = 31$

Step 7. Conclusion:

The required value is 31.

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Evaluate: $3 x^{2} - 2 x y + 6 y^{2}$ when $x = 1, y = - 2$ .

Short Answer

Step by step solution

Step 1. Given Information:

Step 2. Substitute the values:

Step 3. Calculate the exponents:

Step 4. Multiply:

Step 5. Perform Subtraction:

Step 6. Perform Addition:

Step 7. Conclusion:

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Evaluate: 3x2−2xy+6y2 when x=1,y=−2.

Short Answer

Step by step solution

Step 1. Given Information:

Step 2. Substitute the values:

Step 3. Calculate the exponents:

Step 4. Multiply:

Step 5. Perform Subtraction:

Step 6. Perform Addition:

Step 7. Conclusion:

One App. One Place for Learning.

Most popular questions from this chapter

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Evaluate: $3 x^{2} - 2 x y + 6 y^{2}$ when $x = 1, y = - 2$ .