Chapter 1: Q. 231 (page 54)

$\begin{array}{l} Inthefollowingexercise,evaluate. \\ 2 x^{2} y^{3} When \\ x = - \frac{2}{3} and y = - \frac{1}{2} \end{array}$

Short Answer

Expert verified

$Theresultonevaluatingtheexpressionis- \frac{1}{9} .$

Step by step solution

Step 1. Given information

$\begin{array}{l} Thegivenexpressionis \\ 2 x^{2} y^{3} \\ Also, \\ x = - \frac{2}{3} and y = - \frac{1}{2} \\ Wewillevaluatetheexpressionforgivenvaluesof x and y . \end{array}$

Step 2. Substitute the value of x and y in the given expression

$\begin{array}{l} At x = - \frac{2}{3} and y = - \frac{1}{2}, Wehave \\ \Rightarrow 2 {(- \frac{2}{3})}^{2} {(- \frac{1}{2})}^{3} \\ = 2 (\frac{4}{9}) (- \frac{1}{8}) \\ = \frac{2 \times 4 \times (- 1)}{9 \times 8} \\ = - \frac{8}{9 \times 8} \\ = - \frac{1}{9} \end{array}$

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$\begin{array}{l} Inthefollowingexercise,evaluate. \\ 2 x^{2} y^{3} When \\ x = - \frac{2}{3} and y = - \frac{1}{2} \end{array}$

Short Answer

Step by step solution

Step 1. Given information

Step 2. Substitute the value of x and y in the given expression

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Inthefollowingexercise,evaluate.2x2y3Whenx=−23andy=−12

Short Answer

Step by step solution

Step 1. Given information

Step 2. Substitute the value of x and y in the given expression

One App. One Place for Learning.

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$\begin{array}{l} Inthefollowingexercise,evaluate. \\ 2 x^{2} y^{3} When \\ x = - \frac{2}{3} and y = - \frac{1}{2} \end{array}$