Chapter 3: Q 3.53. (page 283)

Find the equation of a horizontal line containing the point $(- 3, 8)$ .

Short Answer

Expert verified

The equation is $y = 8$ .

Step by step solution

Step 1. Use the point-slope form

The point-slope form of an equation of a line with slope $m$ and containing the point $(x_{1}, y_{1})$ is $y - y_{1} = m (x - x_{1})$ .

Step 2. Identify the slope and the point

Every horizontal line has slope $0$ .

So the slope is:

$m = 0$

The point is:

$(x_{1}, y_{1}) = (- 3, 8)$

Step 3. Substitute the values into the point-slope form

$y - y_{1} = m (x - x_{1}) y - 8 = 0 (x - (- 3)) y - 8 = 0 y = 8$

The equation of line is $y = 8$ .

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Find the equation of a horizontal line containing the point $(- 3, 8)$ .

Short Answer

Step by step solution

Step 1. Use the point-slope form

Step 2. Identify the slope and the point

Step 3. Substitute the values into the point-slope form

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Find the equation of a horizontal line containing the point(-3,8).

Short Answer

Step by step solution

Step 1. Use the point-slope form

Step 2. Identify the slope and the point

Step 3. Substitute the values into the point-slope form

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Calculus

Geometry

Probability and Statistics

Discrete Mathematics

Pure Maths

Theoretical and Mathematical Physics

Study anywhere. Anytime. Across all devices.

Find the equation of a horizontal line containing the point $(- 3, 8)$ .