Find an equation of a line perpendicular to the line y=12x-3that contains the point (6,4). Write the equation in slope-intercept form.

Short Answer

Expert verified

The equation isy=-2x+16

Step by step solution

01

Step 1. Find the slope of the given line

The given line is:

y=12x-3

The line is in slope-intercept form. Therefore, its slope is:

m=12

02

Step 2. Find the slope of the perpendicular line and identify the point

The slopes of perpendicular lines are negative reciprocals.

Therefore, the slope of the perpendicular line is:

m1=-2

And the given point is (6,4).

(x1,y1)=(6,4)

03

Step 3. Substitute the values into the point-slope form

The point-slope form is:

y-y1=m(x-x1)y-4=-2(x-6)y-4=-2x+12

04

Step 4. Write the equation in slope-intercept form

The slope-intercept form of the perpendicular line isy=-2x+16.

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