Chapter 3: Q. 394 (page 353)

In the following exercises, determine which ordered pairs are solutions to the given equations.
$y = 6 x - 2$
$(1, 4)$
$(\frac{1}{3}, 0)$
$(6, - 2)$

Short Answer

Expert verified

The solutions to the given equation are

$(1, 4)$
$(\frac{1}{3}, 0)$

Step by step solution

. Given information

Equation is $y = 6 x - 2$ .......equation (1)

Points are

$(1, 4)$
$(\frac{1}{3}, 0)$
$(6, - 2)$

Part (a) Step 1. Check point (1,4)

Substitute $x = 1, y = 4$ in equation (1)

L.H.S.= $4$

R.H.S.=

$6 \times 1 - 2 = 6 - 2 = 4$

here L.H.S.=R.H.S.

So the point (1,4) is the solution to the equation.

Part(b) Step 1. To check point 13,0

Substitute $x = \frac{1}{3}, y = 0$ in equation (1)

L.H.S.=0

R.H.S=

. $6 \times \frac{1}{3} - 2 = 2 - 2 = 0$

here L.H.S.=R.H.S.

So the point $(\frac{1}{3}, 0)$ is the solution to the equation.

Part(c) Step 1. To check point (6,-2)

Substitute $x = 6, y = - 2$ in equation (1)

L.H.S.=-2

R.H.S=
localid="1645008586176" $6 \times 6 - 2 = 36 - 2 = 34$

Since

$- 2 \neq 34$

Hence (6,-2) is not a solution to the equation.

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In the following exercises, determine which ordered pairs are solutions to the given equations.
$y = 6 x - 2$
$(1, 4)$
$(\frac{1}{3}, 0)$
$(6, - 2)$

Short Answer

Step by step solution

. Given information

Part (a) Step 1. Check point (1,4)

Part(b) Step 1. To check point 13,0

Part(c) Step 1. To check point (6,-2)

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In the following exercises, determine which ordered pairs are solutions to the given equations. y=6x-2(1,4)13,06,-2

Short Answer

Step by step solution

. Given information

Part (a) Step 1. Check point (1,4)

Part(b) Step 1. To check point 13,0

Part(c) Step 1. To check point (6,-2)

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Theoretical and Mathematical Physics

Probability and Statistics

Mechanics Maths

Statistics

Calculus

Applied Mathematics

Study anywhere. Anytime. Across all devices.

In the following exercises, determine which ordered pairs are solutions to the given equations.
$y = 6 x - 2$
$(1, 4)$
$(\frac{1}{3}, 0)$
$(6, - 2)$