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Chapter 3: Q.477 (page 358)

In the following exercises, find an equation of a line perpendicular to the given line and contains the given point. Write the equation in slope–intercept form.

line x = −5 point (2, 1)

Short Answer

Expert verified

Equation of the line perpendicular to x = -5 and passing though the point (2, 1) is y = 1.

Step by step solution

01

Step 1. Given information

We have given equation of the line is x = -5 and point is (2, 1).

02

Step 2. Concept

The line that is perpendicular to x = c is a horizontal line, because horizontal and vertical lines are perpendicular.

03

Step 3. Explanation

Here we have given equation is x = -5 which is the vertical line.

We know that the horizontal and vertical lines are perpendicular.

So the line passing though (2, 1) and perpendicular to x = -5 is y = 1.

04

Step 4. Conclusion

Hence, equation of the line perpendicular to x = -5 and passing though the point (2, 1) is

y = 1.

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Most popular questions from this chapter

In the following exercises, use slopes and y-intercepts to determine if the lines are parallel, perpendicular, or neither.

y=-1 andy=2

Determine whether each equation is a function.

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