Determine whether each ordered pair is a solution to the inequality x + y > 4.

ⓐ (6, 1) ⓑ (−3, 6) ⓒ (3, 2) ⓓ (−5, 10) ⓔ (0, 0)

we have given inequality is x + y > 4 and ordered pair is (6, 1).

The solution of a linear inequality in two variables, like Ax + By > C, is anordered pair (x, y) that produces a true statement when the values of x and y are substituted into the inequality.

We have given inequality is,

x + y > 4

Now substituting the given ordered pairs, (6, 1)

Substituting 6 for x and 1 for y,

6 + 1 > 4

7 > 4

Yes the ordered pair (6, 1) is the solution of given inequality.

Hence, ordered pairs (6, 1) is the solution of the given inequality x + y > 4.

We have given inequality is,

x + y > 4

Now substituting the given ordered pair

(-3, 6)

Substituting -3 for x and 6 for y,

-3 + 6 > 4

=> 3 > 4

We know that the 3 is less than 4 it means the ordered pair (-3, 6) is not the solution of the given inequality.

We have given inequality is,

x + y > 4

Now substituting the given ordered pair

(3, 6),

Substituting 3 for x and 6 for y,

3 + 6 > 4

=> 9 > 4

We know that the 4 is less than 9 it means the ordered pair (3, 6) is the solution of the given inequality.

We have given inequality is,

x + y > 4

Now substituting the given ordered pair

(-5, 10),

Substituting -5 for x and 10 for y,

-5 + 10 > 4

=> 5 > 4

So the order pair (-5, 10) is the solution of given inequality.

We have given inequality is,

x + y > 4

Now substituting the given ordered pair,

(0, 0)

Substituting 0 for x and y,

0 + 0 > 4

=> 0 > 4

We know that the 0 is less than 4.

So ordered pair (0, 0) is not the solution of the given inequality.