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Intermediate Algebra

OPENSTAX

$Math Studyset Vaia Explanations$ Math

OER 2017 Edition · 1346 pages

ISBN: 9780998625720

Chapter 5: 290. (page 551)

$\frac{18 a^{4} b^{8}}{- 27 a^{9} b^{5}}$

Short Answer

Expert verified

$\frac{- 2 b^{3}}{3 a^{5}}$

Step by step solution

01

Step 1

Use fraction multiplication.

02

Step 2

Use quotient property to simplify.

$= \frac{18}{- 27} . \frac{a^{4}}{a^{9}} . \frac{b^{8}}{b^{5}} = \frac{- 2}{3} . \frac{1}{a^{5}} . 63$

03

Step 3

Multiply the results to get the answer.

= \frac{- 2 b^{3}}{3 a^{5}}

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Most popular questions from this chapter

Use the Product Property for Exponents to explain $x \cdot x = x^{2}$

Simplify ${(4 x^{3})}^{3} {(2 x^{5})}^{4}$

Convert (a) $- 8.3 \times 10^{2}$ (b) $3.8 \times 10^{- 2}$ to decimal form.

In the following exercises . Simplify the expression

Multiply each pair of conjugates using the product of the conjugates pattern.

$(11 k + 4) (11 k - 4)$

See all solutions

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