Chapter 5: Q. 311 (page 551)

Divide each polynomial by the binomial.
$(2 n^{3} - 10 n + 28) \div (n + 3)$

Short Answer

Expert verified

The solution is $(2 n^{2} - 6 n + 8 + \frac{4}{n + 3})$ .

Step by step solution

Step 1. Given information

Polynomial: $2 n^{3} - 10 n + 28$

Binomial: $n + 3$

Step 2. Calculation

Using long division -

$2 n^{2} - 6 n + 8 + \frac{4}{n + 3}$

role="math" localid="1645987521816" $n + 3 \bar{) 2 n^{3} - 10 n + 28}$

$2 n^{3} + 6 n^{2}$

role="math" localid="1645987672151" $\bar{- 6 n^{2} - 10 n + 28}$

$- 6 n^{2} - 18 n$

role="math" localid="1645987770440" $\bar{8 n + 28}$

$8 n + 24$

$\bar{4}$

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Divide each polynomial by the binomial.
$(2 n^{3} - 10 n + 28) \div (n + 3)$

Short Answer

Step by step solution

Step 1. Given information

Step 2. Calculation

One App. One Place for Learning.

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Divide each polynomial by the binomial.2n3-10n+28÷n+3

Short Answer

Step by step solution

Step 1. Given information

Step 2. Calculation

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Pure Maths

Mechanics Maths

Logic and Functions

Probability and Statistics

Discrete Mathematics

Statistics

Study anywhere. Anytime. Across all devices.

Divide each polynomial by the binomial.
$(2 n^{3} - 10 n + 28) \div (n + 3)$