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Intermediate Algebra

OPENSTAX

$Math Studyset Vaia Explanations$ Math

OER 2017 Edition · 1346 pages

ISBN: 9780998625720

Chapter 5: Q 5.76 (page 542)

Find the quotient $(- 48 a^{8} b^{4} - 36 a^{6} b^{5}) \div (- 6 a^{3} b^{3})$

Short Answer

Expert verified

The quotient is $2 a^{3} b (4 a^{2} + 3 b)$

Step by step solution

01

Step 1. Given information

$(- 48 a^{8} b^{4} - 36 a^{6} b^{5}) \div (- 6 a^{3} b^{3})$

02

Step 2. Divide the polynomial

Rewrite as fraction

$\frac{(- 48 a^{8} b^{4} - 36 a^{6} b^{5})}{(- 6 a^{3} b^{3})}$

Divide each term by the divisor

$\frac{- 48 a^{8} b^{4}}{- 6 a^{3} b^{3}} - \frac{36 a^{6} b^{5}}{- 6 a^{3} b^{3}}$

Simplify

$2 a^{3} b (4 a^{2} + 3 b)$

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Most popular questions from this chapter

Find the product of the below expression.

$(3 p + 8) (3 p - 8)$

Multiply (a) $(3.5 \times 10^{- 4}) (1.6 \times 10^{- 2})$ to get answer in decimal form

Divide (b) $\frac{8 \times 10^{6}}{4 \times 10^{- 1}}$ to get answer in decimal form

Simplify ${(\frac{j^{- 2} j^{5}}{j^{4}})}^{3}$

Convert (a) $- 8.3 \times 10^{2}$ (b) $3.8 \times 10^{- 2}$ to decimal form.

Multiply each pair of conjugates using the product of the conjugates pattern.

$(8 j + 4) (8 j - 4)$

See all solutions

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