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Intermediate Algebra

OPENSTAX

$Math Studyset Vaia Explanations$ Math

OER 2017 Edition · 1346 pages

ISBN: 9780998625720

Chapter 5: Q.231. (page 537)

Multiply each pair of conjugates using the product of the conjugates pattern.
$(9 c + 5) (9 c - 5)$

Short Answer

Expert verified

The solution is $81 c^{2} - 25$ .

Step by step solution

01

Step 1. Given information.

The given expression is $(9 c + 5) (9 c - 5)$ .

02

Step 2. Simplify the expression by using the difference of squares a+ba-b=a2-b2.

Solve it as follows:

$(9 c + 5) (9 c - 5) = {(9 c)}^{2} - {(5)}^{2} \Rightarrow 81 c^{2} - 25$

03

Step 3. Simplified expression.

Hence, the required expression is $81 c^{2} - 25$ .

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Most popular questions from this chapter

In the following exercises , simplify the expression $(4 a^{3} b) (9 a^{2} b^{6})$ .

Convert (a) $- 8.3 \times 10^{2}$ (b) $3.8 \times 10^{- 2}$ to decimal form.

Convert (a) $7.5 \times 10^{6}$ (b) $- 4.13 \times 10^{- 5}$ to decimal form.

Simplify ${(2 p q^{4})}^{3} {(5 p^{6} q)}^{2}$

Multiply each pair of conjugates using the product of the conjugates pattern.

$(11 k + 4) (11 k - 4)$

See all solutions

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