Chapter 9: Q. 141 (page 898)

In the following exercises, solve by using the Quadratic Formula.
$16 c^{2} + 24 c + 9 = 0$

Short Answer

Expert verified

The solution of the given equation is $c = - \frac{3}{4}$ .

Step by step solution

Step 1. Given information

The given equation is:

$16 c^{2} + 24 c + 9 = 0$

Step 2. Substitute the values in Quadratic Formula.

Quadratic Formula for the equation $a x^{2} + b x + c = 0$ is:

$x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$

In the given equation, $a = 16, b = 24, c = 9$ . Substitute these values in Quadratic Formula.

$c = \frac{- 24 \pm \sqrt{(24)^{2} - 4 (16) (9)}}{2 (16)}$

Step 3. Simplify the value.

On simplification, we get

$\begin{array}{rcl} c & = & \frac{- 24 \pm \sqrt{576 - 576}}{32} \\ c & = & \frac{- 24 \pm 0}{32} \\ c & = & \frac{- 24}{32} \\ c & = & - \frac{3}{4} \end{array}$

Step 4. Conclusion.

The solution of the given equation is $c = - \frac{3}{4}$ .

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In the following exercises, solve by using the Quadratic Formula.
$16 c^{2} + 24 c + 9 = 0$

Short Answer

Step by step solution

Step 1. Given information

Step 2. Substitute the values in Quadratic Formula.

Step 3. Simplify the value.

Step 4. Conclusion.

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In the following exercises, solve by using the Quadratic Formula.16c2+24c+9=0

Short Answer

Step by step solution

Step 1. Given information

Step 2. Substitute the values in Quadratic Formula.

Step 3. Simplify the value.

Step 4. Conclusion.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Applied Mathematics

Probability and Statistics

Calculus

Theoretical and Mathematical Physics

Discrete Mathematics

Decision Maths

Study anywhere. Anytime. Across all devices.

In the following exercises, solve by using the Quadratic Formula.
$16 c^{2} + 24 c + 9 = 0$