Chapter 9: Q. 19 (page 869)

In the following exercises, solve each equation.
$7 p^{2} + 10 = 26$

Short Answer

Expert verified

The solution of the equation is $p = 4 \sqrt{\frac{1}{7}}, - 4 \sqrt{\frac{1}{7}}$

Step by step solution

Step 1. Given information

In the given question we have to solve given equation.
$7 p^{2} + 10 = 26$

Step 2. The given equation is 7p2+10=26

Isolate the quadratic term.

Subtract 10 on both side

$7 p^{2} + 10 - 10 = 26 - 10 7 p^{2} = 16$

Divide by 7 on both side

$\frac{7}{7} p^{2} = \frac{16}{7} p^{2} = \frac{16}{7}$

Step 3. Use the Square Root Property.

$p = \pm \sqrt{\frac{16}{7}}$

Simplify the radical.

$p = \pm 4 \sqrt{\frac{1}{7}}$

Step 4. Rewrite to show two solutions.

$p = 4 \sqrt{\frac{1}{7}} p = - 4 \sqrt{\frac{1}{7}}$

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In the following exercises, solve each equation.
$7 p^{2} + 10 = 26$

Short Answer

Step by step solution

Step 1. Given information

Step 2. The given equation is 7p2+10=26

Step 3. Use the Square Root Property.

Step 4. Rewrite to show two solutions.

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In the following exercises, solve each equation.7p2+10=26

Short Answer

Step by step solution

Step 1. Given information

Step 2. The given equation is 7p2+10=26

Step 3. Use the Square Root Property.

Step 4. Rewrite to show two solutions.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Decision Maths

Applied Mathematics

Logic and Functions

Theoretical and Mathematical Physics

Probability and Statistics

Geometry

Study anywhere. Anytime. Across all devices.

In the following exercises, solve each equation.
$7 p^{2} + 10 = 26$