Chapter 7: Q 439 (page 737)

In the following exercise solve $\frac{v - 15}{v^{2} - 9 v + 18} = \frac{4}{v - 3} + \frac{2}{v - 6}$

Short Answer

Expert verified

The solution is $v = 3$

Step by step solution

Step 1. Given Information

$\frac{v - 15}{v^{2} - 9 v + 18} = \frac{4}{v - 3} + \frac{2}{v - 6}$

Step 2. Solve.

The least common denominator of all denominators in the equation is $(v - 3) (v - 6)$

Clear the fraction by multiplying both sides of the equation by the LCD.

$(v - 3) (v - 6) (\frac{v - 15}{v^{2} - 9 v + 18}) = (v - 3) (v - 6) (\frac{4}{v - 3} + \frac{2}{v - 6}) (v - 3) (v - 6) (\frac{v - 15}{v^{2} - 9 v + 18}) = (v - 3) (v - 6) (\frac{4}{v - 3}) + (v - 3) (v - 6) (\frac{2}{v - 6}) (v - 15) = (v - 6) 4 + (v - 3) 2 v - 15 = 6 v - 30 5 v = 15 v = 3$

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In the following exercise solve $\frac{v - 15}{v^{2} - 9 v + 18} = \frac{4}{v - 3} + \frac{2}{v - 6}$

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Solve.

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In the following exercise solvev-15v2-9v+18=4v-3+2v-6

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Solve.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Theoretical and Mathematical Physics

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Study anywhere. Anytime. Across all devices.

In the following exercise solve $\frac{v - 15}{v^{2} - 9 v + 18} = \frac{4}{v - 3} + \frac{2}{v - 6}$