Chapter 7: Q. 7.69 (page 686)

Solve: $\frac{2}{x + 1} + \frac{1}{x - 1} = \frac{1}{x^{2} - 1}$ .

Short Answer

Expert verified

The solution is $x = \frac{2}{3}$

Step by step solution

Step 1. Given.

The given equation is: $\frac{2}{x + 1} + \frac{1}{x - 1} = \frac{1}{x^{2} - 1}$ .

Step 2. To find

We have to solve the given equation.

Step 3. Calculation

The LCD is $(x + 1) (x - 2)$ . Multiply both sides of the equation by LCD. Then we solve the linear equation.

$\frac{2}{x + 1} + \frac{1}{x - 1} = \frac{1}{x^{2} - 1} \frac{2}{x + 1} (x + 1) (x - 1) + \frac{1}{x - 1} (x + 1) (x - 1) = \frac{1}{x^{2} - 1} (x + 1) (x - 1) 2 (x - 1) + (x + 1) = 1 2 x - 2 + x + 1 = 1 3 x - 1 = 1 3 x = 1 + 1 3 x = 2 x = \frac{2}{3}$

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Solve: $\frac{2}{x + 1} + \frac{1}{x - 1} = \frac{1}{x^{2} - 1}$ .

Short Answer

Step by step solution

Step 1. Given.

Step 2. To find

Step 3. Calculation

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Solve:2x+1+1x-1=1x2-1.

Short Answer

Step by step solution

Step 1. Given.

Step 2. To find

Step 3. Calculation

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Mechanics Maths

Theoretical and Mathematical Physics

Probability and Statistics

Discrete Mathematics

Decision Maths

Statistics

Study anywhere. Anytime. Across all devices.

Solve: $\frac{2}{x + 1} + \frac{1}{x - 1} = \frac{1}{x^{2} - 1}$ .