Chapter 7: Q. 79 (page 667)

In the following exercises, add.
$\frac{2 r^{2}}{2 r - 1} + \frac{15 r - 8}{2 r - 1}$

Short Answer

Expert verified

The simplified expression is $r + 8$ but $r \neq \frac{1}{2}$ .

Step by step solution

Step 1. Given Information

The given expression is $\frac{2 r^{2}}{2 r - 1} + \frac{15 r - 8}{2 r - 1}$

Step 2. Add the numerator

As the denominator is the same for both the terms, add the numerator and place it over the common denominator.

$\frac{2 r^{2}}{2 r - 1} + \frac{15 r - 8}{2 r - 1} = \frac{2 r^{2} + 15 r - 8}{2 r - 1}$

Step 3. Factor the numerator

Factor the expression in the numerator and then cancel out the common terms from the numerator and denominator.

$\frac{(2 r - 1) (r + 8)}{(2 r - 1)} = r + 8$

So, the resultant expression is $r + 8$ but the denominator of the given expression was $2 r - 1$ , so, $r \neq \frac{1}{2}$ .

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In the following exercises, add.
$\frac{2 r^{2}}{2 r - 1} + \frac{15 r - 8}{2 r - 1}$

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Add the numerator

Step 3. Factor the numerator

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In the following exercises, add.2r22r-1+15r-82r-1

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Add the numerator

Step 3. Factor the numerator

One App. One Place for Learning.

Most popular questions from this chapter

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In the following exercises, add.
$\frac{2 r^{2}}{2 r - 1} + \frac{15 r - 8}{2 r - 1}$