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Intermediate Algebra

OPENSTAX

$Math Studyset Vaia Explanations$ Math

OER 2017 Edition · 1346 pages

ISBN: 9780998625720

Chapter 8: Q. 546RE (page 854)

In the following exercises, solve $\sqrt{10 + 2 c} = \sqrt{4 c + 16}$

Short Answer

Expert verified

Solution is $c = - 3$

Step by step solution

01

Given information

Solve $\sqrt{10 + 2 c} = \sqrt{4 c + 16}$

02

Solution

We have

$\sqrt{10 + 2 c} = \sqrt{4 c + 16} 10 + 2 c = 4 c + 16 2 c = - 6 c = \frac{- 6}{2} c = - 3$

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Most popular questions from this chapter

In the following exercises, write with a rational exponent.

$ⓐ \sqrt[8]{r} ⓑ \sqrt[10]{s} ⓒ \sqrt[4]{t}$

In the following exercises, use the Product Property to simplify radical expression $\sqrt{27}$ .

In the following exercises, simplify.

(a) $- 9^{\frac{3}{2}}$

(b) $- 9^{- \frac{3}{2}}$

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Simplify:

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Simplify: $\sqrt{\frac{24 p^{3}}{49}} .$

See all solutions

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