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Intermediate Algebra

OPENSTAX

$Math Studyset Vaia Explanations$ Math

OER 2017 Edition · 1346 pages

ISBN: 9780998625720

Chapter 8: Q. 558RE (page 855)

In the following exercises, find the domain of the function and write the domain in interval notation.
$f (x) = \sqrt[3]{4 x^{2} - 16}$

Short Answer

Expert verified

Domain is $x \in (- \infty, \infty)$

Step by step solution

01

Given information

Domain of $f (x) = \sqrt[3]{4 x^{2} - 16}$

02

Solution

We have

$f (x) = \sqrt[3]{4 x^{2} - 16}$

For all the values of $x$ the value of $f (x)$ is defined

Hence domain is $x \in (- \infty, \infty)$

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Most popular questions from this chapter

In the following exercises, solve.
$\sqrt[3]{4 x - 1} = 3$

Write as a radical expression:

(a) $t^{\frac{1}{2}}$

(b) $m^{\frac{1}{3}}$

(c) $r^{\frac{1}{4}}$

In the following exercises, use the Product Property to simplify radical expressions $\sqrt{96}$

In the following exercises, write with a rational exponent.

$(a) \sqrt[5]{u^{2}} (b) (\sqrt[3]{6 x})^{5} (c) \sqrt[4]{{(\frac{18 a}{5 b})}^{7}}$

In the following exercises, simplify using absolute value signs as needed. $\sqrt{175 n^{13}}, \sqrt[5]{512 p^{5}}, \sqrt[4]{324 q^{7}}$

See all solutions

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