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Intermediate Algebra

OPENSTAX

$Math Studyset Vaia Explanations$ Math

OER 2017 Edition · 1346 pages

ISBN: 9780998625720

Chapter 8: Q. 600 (page 857)

In the following exercises, solve.
$\sqrt{2 x + 5} + 8 = 6$

Short Answer

Expert verified

The solution of the given expression is $x = - \frac{1}{2} .$

Step by step solution

01

Step 1. Given Information

We have $\sqrt{2 x + 5} + 8 = 6 \sqrt{2 x + 5} = - 2$

02

Step 2. Squaring both sides

$(2 x + 5) = {(- 2)}^{2} 2 x + 5 = 4$

03

Step 3. Simplify the expression

$2 x = 4 - 5 2 x = - 1 x = - \frac{1}{2}$

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Most popular questions from this chapter

Simplify:

a. $y^{\frac{3}{4}} \cdot y^{\frac{5}{8}}$ b. ${(m^{9})}^{\frac{2}{9}}$ c. $\frac{d^{\frac{1}{5}}}{d^{\frac{6}{5}}}$

Use the Quotient Property to simplify square roots.

(a) $\frac{\sqrt{80 q^{5}}}{\sqrt{5 q}}$

(b) $\frac{\sqrt[3]{- 625}}{\sqrt[3]{5}}$

(c) $\frac{\sqrt[4]{80 m^{7}}}{\sqrt[4]{5 m}}$

Explain why $\sqrt[4]{- 64}$ is not a real number but $\sqrt[3]{- 64}$ is.

In the following exercises, simplify.

(a) $32^{\frac{2}{5}}$

(b) role="math" localid="1644741549807" $27^{- \frac{2}{3}}$

(c) ${(- 25)}^{\frac{1}{2}}$

In the following exercises, solve.
$\sqrt{2 u - 3} + 2 = 0$

See all solutions

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