In the following exercise, write the first five terms of the sequence whose general term is given.

an=3n+33n

Short Answer

Expert verified

The first five terms of the sequence whose general term isan=3n+33nare2,1,49,527,227.

Step by step solution

01

Step 1. Given information

Thegeneraltermforthesequenceisgivenasan=3n+33nWehavetofindthefirstfivetermsofthesequence.

02

Step 2. Calculating the terms

Wewillsubstituten=1,2,3,4and5intheordertoobtainthefirstfivetermsofthesequence.Now,

n:12345an:a1=31+331=3+33=63=2a2=32+332=6+39=99=1a3=33+333=9+327=1227=49a4=34+334=12+381=1581=527a5=35+335=15+3243=18243=227

03

Step 3. Conclusion

From the above step, we can conclude that the first five terms of the sequence will be2,1,49,527,227.

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