Chapter 12: Q. 267 (page 1218)

Find the thirtieth term of a sequence where the first term is $16$ and the common difference is $- 5$ .

Short Answer

Expert verified

The thirtieth term of a sequence is $- 44$

Step by step solution

Step 1. Given information

The first term of the series is $16$

The common difference is $- 5$

We have to find the $13^{t h}$ term of the series.

Step 2. Using formula to find the term.

The general term of the arithmetic series with the first term $a_{1}$ and common difference $d$ is: role="math" localid="1645296479868" $a_{n} = a_{1} + (n - 1) d$

We have, $n = 13 a_{1} = 16 d = - 5$

Step 3. Put the values to find the term

Put the obtained value in the formula:

$a_{n} = a_{1} + (n - 1) d a_{13} = 16 + (13 - 1) (- 5) a_{13} = 16 + (12) (- 5) a_{13} = 16 - 60 a_{13} = - 44$

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Find the thirtieth term of a sequence where the first term is $16$ and the common difference is $- 5$ .

Short Answer

Step by step solution

Step 1. Given information

Step 2. Using formula to find the term.

Step 3. Put the values to find the term

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Find the thirtieth term of a sequence where the first term is 16 and the common difference is -5.

Short Answer

Step by step solution

Step 1. Given information

Step 2. Using formula to find the term.

Step 3. Put the values to find the term

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Logic and Functions

Theoretical and Mathematical Physics

Mechanics Maths

Applied Mathematics

Calculus

Discrete Mathematics

Study anywhere. Anytime. Across all devices.

Find the thirtieth term of a sequence where the first term is $16$ and the common difference is $- 5$ .