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Intermediate Algebra

OPENSTAX

$Math Studyset Vaia Explanations$ Math

OER 2017 Edition · 1346 pages

ISBN: 9780998625720

Chapter 12: Q 90. (page 1184)

Find the twenty-third term of a sequence where the first term is six and the common difference is four.

Short Answer

Expert verified

96

Step by step solution

01

Step 1. Given Information.

The first term is six and the common difference is four.

02

Step 2. Formula used.

Write the formula of an arithmetic sequence.

a_{n} = a_{1} + (n - 1) d

Wherea₁ is the first term andd is a common difference.

03

Step 3. Find the twenty-third term.

Substitute 6 for the first term, 4 for d, and 23 for nin the above formula.

$\begin{array}{rcl} a_{23} & = & 6 + (23 - 1) 4 \\ = & 6 + 88 \\ = & 94 \end{array}$

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Most popular questions from this chapter

In the following exercises, write the first five terms of each geometric sequence with the given first term and common ratio.

$a_{1} = 64$ and $r = \frac{1}{4}$

Write the first five terms of the sequence where the first term is $7$ and the common ratio is $r = - 3$ .

Find a general term for the sequence whose first five terms are shown.

$\frac{1}{1}, \frac{1}{4}, \frac{1}{9}, \frac{1}{16}, \frac{1}{25}, \dots$

Write the sum using summation notation: $1 + \frac{1}{4} + \frac{1}{9} + \frac{1}{16} + \frac{1}{25}$ .

Write the first five terms of the sequence whose general term is $a_{n} = \frac{n!}{(n + 1)!}$ .

See all solutions

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