Chapter 2: Q 1 (page 111)

In the following exercises, determine whether the given values are solutions to the equation.
$6 y + 10 = 12 y$
$y = \frac{5}{3}$
$y = - \frac{1}{2}$

Short Answer

Expert verified

$y = \frac{5}{3}$ is the solution for the equation $6 y + 10 = 12 y$

Step by step solution

Step 1. Given information

The equation is $6 y + 10 = 12 y$

Find value of y and choose correct option.

Step 2. Calculation

Combine like terms of the equation $6 y + 10 = 12 y$

$6 y - 12 y = - 10 - 6 y = - 10$

Divide by $- 6$ on both sides

$y = \frac{10}{6} y = \frac{5}{3}$

Correct option is a. $y = \frac{5}{3}$

Step 3. Explanation for wrong option

Substitute $y = - \frac{1}{2}$ in equation $6 y + 10 = 12 y$

$6 (- \frac{1}{2}) + 10 = 12 (- \frac{1}{2}) - 3 + 10 = - 6 7 \neq - 6$

so this is wrong option.

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In the following exercises, determine whether the given values are solutions to the equation.
$6 y + 10 = 12 y$
$y = \frac{5}{3}$
$y = - \frac{1}{2}$

Short Answer

Step by step solution

Step 1. Given information

Step 2. Calculation

Step 3. Explanation for wrong option

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In the following exercises, determine whether the given values are solutions to the equation.6y+10=12yy=53y=-12

Short Answer

Step by step solution

Step 1. Given information

Step 2. Calculation

Step 3. Explanation for wrong option

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Logic and Functions

Pure Maths

Probability and Statistics

Theoretical and Mathematical Physics

Statistics

Decision Maths

Study anywhere. Anytime. Across all devices.

In the following exercises, determine whether the given values are solutions to the equation.
$6 y + 10 = 12 y$
$y = \frac{5}{3}$
$y = - \frac{1}{2}$