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Chapter 2: Q. 249 (page 164)

Mukul has $3.75 in quarters, dimes and nickels in his pocket. He has five more dimes than quarters and nine more nickels than quarters. How many of each coin are in his pocket?

Short Answer

Expert verified

The number of Quarters is = 7

The number of Dimes is = 12

The Number of Nickels is = 16

Step by step solution

01

Step 1.  Given Data

Mukul has $3.75 in quarters, dimes and nickels in his pocket. He has five more dimes than quarters and nine more nickels than quarters.

02

Step 2.  To Find

How many of each coin are in his pocket?

03

Step 3.  Explanation

Let The number of Quarters is = P

The number of Dimes is = P+5

The Number of Nickels is = P+9

TypeNumber×Value($)=TotalValue($)
QuartersP0.250.25P
NickelsP+90.050.05(P+9)
DimesP+50.10.1(P+5)



$3.75
04

Step 4.  Calculation

after analyzing the table, We see that - 0.25P+0.05(P+9)+0.1(P+5)=3.75

0.25P+0.05P+0.45+0.1P+0.5=3.75

0.25P+0.05P+0.1P=3.75-0.5-0.45

0.4P=2.8

P=7

The number of Quarters is = 7

The number of Dimes is = P+5

= 12

The Number of Nickels is = P+9

= 16

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