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Chapter 2: Q. 2.69 (page 139)

The length of a rectangle is seven more than twice the width. The perimeter is 110 inches. Find the length and width.

Short Answer

Expert verified
  • The length of rectangle is 39 inches.
  • The width of rectangle is 16 inches.

Step by step solution

01

Step 1. Given Information

  • The length of a rectangle is seven more than twice the width.
  • The perimeter is 110 inches.

We have to find the length and the width of rectangle.

02

Step 2. Name

Choose a variable to represent the width.

Let w = width.

The length is seven more than twice the width.

2w + 7 = length

Perimeter = P = 110 inches

03

Step 3. Translate.

Write the appropriate formula.

P=2l+2w

Substitute in the given information.

110=2(2w+7)+2w

04

Step 4. Solve the equation.110=4w+14+2w

110=6w+1496=6w16=w(width)16Thewidthis16inches.2w+7(length)2(16)+739Thelengthis39inches

05

Step 5. Check.

P=2l+2w110=2×39+2×16110=78+32110=110verified

The length is 39 inches and the width is 16 inches.

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