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Chapter 2: Q. 2.70 (page 139)

The width of a rectangle is eight yards less than twice the length. The perimeter is 86 yards. Find the length and width.

Short Answer

Expert verified
  • The length of rectangle is 17 yards.
  • The width of rectangle is 26 yards.

Step by step solution

01

Step 1. Given Information

  • The width of a rectangle is eight yards less than twice the length.
  • The perimeter is 86 yards.

We have to find the length and the width of rectangle.

02

Step 2. Name 

Choose a variable to represent the length.

Let l = length.

The width is eight less than twice the length.

2l - 8 = width

Perimeter = P = 86 yards

03

Step 3. Translate.

Write the appropriate formula.

P=2l+2w

Substitute in the given information.

86=2l+2(2l-8)

04

Step 4. Solve the equation. 

86=2l+4l-1686=6l-16102=6l17=l(length)Thelengthis17yards2l-8(width)2(17)-8=26Thewidthis26yards

05

Step 5. Check

P=2l+2w86=2×17+2×2686=34+5286=86verified

The length is 17 yards and the width is 26 yards..

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