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Chapter 2: Q. 219 (page 146)

The perimeter of a rectangle of 150 feet. The length of the rectangle is twice the width. Find the length and width of the rectangle.

Short Answer

Expert verified

The length of the rectangle is 50 feet and the width is 25 feet.

Step by step solution

01

Step 1. Given Information

  • The perimeter of the rectangle is 150 feet.
  • The length of the rectangle is twice its width.
02

Step 2. Define the variables

  • Let the width of the rectangle is wfeet.
  • So, its length will be2wfeet.
03

Step 3. Use the formula of Perimeter

  • Use the formula of perimeter, P=2w+2land substitute P=150,l=2winto the formula and solve for the unknown variable.

150=2w+22w150=6ww=25

  • So, the width of the rectangle is 25 feet.
04

Step 4. Find the Length

  • Substitute w=25into l=2wand solve tofind the length.

l=2×25=50

  • So, the length of the rectangle 50 feet.
05

Step 5. Conclusion

The length of the rectangle is 50 feet and the width is 25 feet.

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