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Chapter 2: Q. 229 (page 147)

A rectangular parking lot has perimeter 250 feet. The length is five feet more than twice the width. Find the length and width of the parking lot.

Short Answer

Expert verified

The length of the parking lot is 85 feet and the width is 40 feet.

Step by step solution

01

Step 1. Given Information

  • The perimeter of the parking lot is 250 feet.
  • The length is 5 feet more than twice the width.
02

Step 2. Define the Variables

  • Let the width of the parking lot is w feet.
  • So, the length will be2w+5 feet.
03

Step 3. Use the Perimeter Formula

  • Substitute P=250,l=2w+5in the formula of the perimeter of a rectangle, P=2w+2land solve for the unknown variable.

250=2w+22w+5250=6w+106w=240w=40

  • So, the width of the parking lot is 60 feet.
04

Step 4. Find the Length

  • Substitute w=40into5 and solve to find the length.

l=240+5=85

  • So, the length is 85 feet.
05

Step 5. Conclusion

The length of the parking lot is 85 feet and the width is 40 feet.

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