Chapter 4: Q. 286 (page 472)

In the following exercises, solve each system by graphing.
$\{\begin{cases} y \leq 3 x + 2 \\ y > x - 1 \end{cases}$

Short Answer

Expert verified

The darkest region is the solution to the system of equations and the graph is

Step by step solution

Given information

Given the system of equations $\{\begin{cases} y \leq 3 x + 2 \\ y > x - 1 \end{cases}$

Graph the system of equations

The system of equations $y = 3 x + 2$ has intercept The boundary is solid. Testing the point , $(0, 0)$ we get

$0 \leq 0 + 2 0 \leq 2$ which is true

Calculating for second equation

For $y = x - 1$ , the intercepts are $- 1, 1$ and testing the point $(0, 0)$ , we get

$0 > 0 - 1 0 > - 1$ which is true

So both of them contains the origin

Plotting the graph

The graph is

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In the following exercises, solve each system by graphing.
$\{\begin{cases} y \leq 3 x + 2 \\ y > x - 1 \end{cases}$

Short Answer

Step by step solution

Given information

Graph the system of equations

Calculating for second equation

Plotting the graph

One App. One Place for Learning.

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In the following exercises, solve each system by graphing. y≤3x+2y>x-1

Short Answer

Step by step solution

Given information

Graph the system of equations

Calculating for second equation

Plotting the graph

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Probability and Statistics

Statistics

Logic and Functions

Pure Maths

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Mechanics Maths

Study anywhere. Anytime. Across all devices.

In the following exercises, solve each system by graphing.
$\{\begin{cases} y \leq 3 x + 2 \\ y > x - 1 \end{cases}$