Chapter 4: Q. 287 (page 472)

In the following exercises, solve each system by graphing.
$\{\begin{cases} y < - 2 x + 2 \\ y \geq - x - 1 \end{cases}$

Short Answer

Expert verified

The darkest region represent the solution to the system of equations

Step by step solution

Given information

Given the system of equations $\{\begin{cases} y < - 2 x + 2 \\ y \geq - x - 1 \end{cases}$

Graph the system of equations

The system of equations $y = - 2 x + 2$ has the intercept as $1, 2$ . Testing the point $(0, 0)$ , we get

$0 < - 2 (0) + 2 0 < 2$ which is true

Checking for another equation

The equation $y = - x - 1$ has intercept as $- 1, 1$ and the testing point $(0, 0)$ has

$0 \geq 0 - 1 0 \geq - 1$ which is true

Step 4

The graph for the system of equation is

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In the following exercises, solve each system by graphing.
$\{\begin{cases} y < - 2 x + 2 \\ y \geq - x - 1 \end{cases}$

Short Answer

Step by step solution

Given information

Graph the system of equations

Checking for another equation

Step 4

One App. One Place for Learning.

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In the following exercises, solve each system by graphing.y<-2x+2y≥-x-1

Short Answer

Step by step solution

Given information

Graph the system of equations

Checking for another equation

Step 4

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Decision Maths

Mechanics Maths

Theoretical and Mathematical Physics

Geometry

Calculus

Statistics

Study anywhere. Anytime. Across all devices.

In the following exercises, solve each system by graphing.
$\{\begin{cases} y < - 2 x + 2 \\ y \geq - x - 1 \end{cases}$