Chapter 4: Q 291 (page 472)

The darkest region represent the solution to the system of equations $\{\begin{cases} x + 2 y < 4 \\ y < x - 2 \end{cases}$

Short Answer

Expert verified

The darkest region represent the solution to the system of equations

Step by step solution

Given information

Given the system of equations $\{\begin{cases} x + 2 y < 4 \\ y < x - 2 \end{cases}$

Checking the point for the system of equations

The equation $x + 2 y = 4$ has intercept $2, 4$ .Testing the point $(0, 0)$ , we get

$0 + 0 < 4 0 < 4$ which is true

So origin is included

Checking for another equation

The equation $y = x - 2$ has intercept $- 2, 2$ . Testing the point $(0, 0)$ , we get

$0 < 0 - 2 0 < - 2$ which is not true

So origin is not included

Graph of system of equation

The graph is

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The darkest region represent the solution to the system of equations $\{\begin{cases} x + 2 y < 4 \\ y < x - 2 \end{cases}$

Short Answer

Step by step solution

Given information

Checking the point for the system of equations

Checking for another equation

Graph of system of equation

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The darkest region represent the solution to the system of equations x+2y<4y<x-2

Short Answer

Step by step solution

Given information

Checking the point for the system of equations

Checking for another equation

Graph of system of equation

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Theoretical and Mathematical Physics

Pure Maths

Applied Mathematics

Mechanics Maths

Probability and Statistics

Logic and Functions

Study anywhere. Anytime. Across all devices.

The darkest region represent the solution to the system of equations $\{\begin{cases} x + 2 y < 4 \\ y < x - 2 \end{cases}$