Chapter 4: Q 346 (page 479)

In the following exercises, solve the systems of equations by elimination.
$\{\begin{cases} - x + 3 y = 8 \\ 2 x - 6 y = - 20 \end{cases}$

Short Answer

Expert verified

The system of equations $\{\begin{cases} - x + 3 y = 8 \\ 2 x - 6 y = - 20 \end{cases}$ has no solution.

Step by step solution

Step 1. Given Information

We are given a system of equations $\{\begin{cases} - x + 3 y = 8 \\ 2 x - 6 y = - 20 \end{cases}$

The objective is to solve the equation using the elimination method.

Step 2. Using the elimination method

Multiply the first equation by $2$ and add it with the second equation

$\begin{array}{rcl} 2 (- x + 3 y) + 2 x - 6 y & = & 2 \times 8 + (- 20) \\ - 2 x + 6 y + 2 x - 6 y & = & 16 - 20 \\ 0 & = & - 4 \end{array}$

This gives us a false statement. So the given system of equations has no solution.

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In the following exercises, solve the systems of equations by elimination.
$\{\begin{cases} - x + 3 y = 8 \\ 2 x - 6 y = - 20 \end{cases}$

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Using the elimination method

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In the following exercises, solve the systems of equations by elimination.-x+3y=82x-6y=-20

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Using the elimination method

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Calculus

Statistics

Decision Maths

Pure Maths

Theoretical and Mathematical Physics

Applied Mathematics

Study anywhere. Anytime. Across all devices.

In the following exercises, solve the systems of equations by elimination.
$\{\begin{cases} - x + 3 y = 8 \\ 2 x - 6 y = - 20 \end{cases}$