In the following exercises,translate to a system of equations and solve.

Sheila and Lenore were driving to their grandmother's house.Lenore left one hour after sheila.Sheila drove at a rate of 45 mph,and lenore drove at a speed of 60 mph.How long it will take for Lenore catch up to sheila?

Short Answer

Expert verified

3 hours to take for Lenore catch up to sheila

Step by step solution

01

Step 1.Given information

Let x be the length of the time of sheila

Let y represents length of the time of Lenore

The following chart will help us organize the data

NameRateTimeDistance
D=r.t
Sheila45x45x
Lenore60y60y

To make the system of equations,you must recognize that sarah and her sister will drive the same distance

so, 45x=60y

Since Lenore left her house after one hour,her time will be 1 hour less that sheila time,

so y=x-1x=y+1

02

Step 2.Find the time take for Lenore to catch up to sarah

Substitute x=y+1in equation 45x=60yand solve for y.

45x=60y45(y+1)=60y45y+45=60y-15y=-45y=3

Substitute y=3 into y=x-1and solve for x

y=x-13=x-1x=4

03

Step 3.Check

Substitute

Sheila:-

45x=45(4)

=180

Lenore:-

60y=60(3)

180

Yes, they will have to travelled the same distance when they meet.

Therefore,3 hours to take for Lenore to catch up to sheila

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