Chapter 4: Q. 45 (page 386)

In the following exercises, solve the systems of equations by substitution.
$y = - \frac{2}{3} x + 5 2 x + 3 y = 11$

Short Answer

Expert verified

The solution of the system of linear equations has no solutions.

Step by step solution

Step 1. Given Information

The given linear equations are,

$y = - \frac{2}{3} x + 5 2 x + 3 y = 11$

Step 2. Calculation

First solve one equation for one variable.

Solve the first equation for y.

$y = - \frac{2}{3} x + 5$

Substitute $y = - \frac{2}{3} x + 5$ in second equation $2 x + 3 y = 11$ and solve for x.

$2 x + 3 y = 11 2 x + 3 (- \frac{2}{3} x + 5) = 11 2 x - 2 x + 15 = 11 15 = 11$

This is not true.

Therefore, the solution of the system of linear equations has no solutions.

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In the following exercises, solve the systems of equations by substitution.
$y = - \frac{2}{3} x + 5 2 x + 3 y = 11$

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Calculation

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In the following exercises, solve the systems of equations by substitution.y=-23x+52x+3y=11

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Calculation

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In the following exercises, solve the systems of equations by substitution.
$y = - \frac{2}{3} x + 5 2 x + 3 y = 11$