Chapter 4: Q 4.67 (page 427)

Solve the system of equations:
$x + 2 y + 6 z = 5 - x + y - 2 z = 3 x - 4 y - 2 z = 1$

Short Answer

Expert verified

There is no solution of given system of linear equations.

Step by step solution

Step 1. Given Information

We are given a system of linear equation,

$x + 2 y + 6 z = 5 - (1) - x + y - 2 z = 3 - (2) x - 4 y - 2 z = 1 - (3)$

Step 2. Solving the equations

Adding first and second equations, we get

$x - x + 2 y + y + 6 z - 2 z = 5 + 3 3 y + 4 z = 8 - (4)$

Now, adding second and third equations, we get

$- x + x + y - 4 y - 2 z - 2 z = 3 + 1 - 3 y - 4 z = 4 - (5)$

Now, Adding fourth and fifth equation, we get

$3 y - 3 y + 4 z - 4 z = 8 + 4 0 \neq 12$

This is not true hence the given system has no solution.

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Solve the system of equations:
$x + 2 y + 6 z = 5 - x + y - 2 z = 3 x - 4 y - 2 z = 1$

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Solving the equations

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Solve the system of equations:x+2y+6z=5−x+y−2z=3x−4y−2z=1

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Solving the equations

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Decision Maths

Theoretical and Mathematical Physics

Pure Maths

Statistics

Logic and Functions

Discrete Mathematics

Study anywhere. Anytime. Across all devices.

Solve the system of equations:
$x + 2 y + 6 z = 5 - x + y - 2 z = 3 x - 4 y - 2 z = 1$