Chapter 4: Q. 47 (page 386)

In the following exercises, solve the systems of equations by elimination.
$6 x - 5 y = - 1 2 x + y = 13$

Short Answer

Expert verified

The solution for system of linear equation is that $(4, 5)$ .

Step by step solution

Step 1. Given Information

The system of linear equation:

$6 x - 5 y = - 1 . . . . . . . . (1) 2 x + y = 13 . . . . . . . . (2)$

Step 2. Calculation

Here both equations are in standard form. To get opposite coefficients of y multiply second equation with 5.

$5 (2 x + y) = 5 (13) 10 x + 5 y = 65 . . . . . . . . (3)$

Solve for x:

From equations $(1)$ and $(3)$ :

$6 x - 5 y = - 1 10 x + 5 y = 65 16 x = 64 x = \frac{64}{16} x = 4$

Solve for y:

Substitute $x = 4$

in the equation $6 x - 5 y = - 1$ and solve for y.

$6 x - 5 y = - 1 6 (4) - 5 y = - 1 24 - 5 y = - 1 - 5 y = - 1 - 24 - 5 y = - 25 y = \frac{- 25}{- 5} y = 5$

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In the following exercises, solve the systems of equations by elimination.
$6 x - 5 y = - 1 2 x + y = 13$

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Calculation

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Short Answer

Step by step solution

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One App. One Place for Learning.

Most popular questions from this chapter

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In the following exercises, solve the systems of equations by elimination.
$6 x - 5 y = - 1 2 x + y = 13$