Chapter 4: Q. 52 (page 386)

In the following exercises, solve the systems of equations by elimination.
$3 x + 8 y = - 3 2 x + 5 y = - 3$

Short Answer

Expert verified

The solution for the system of linear equation is $(- 9, 3)$ .

Step by step solution

Step 1. Given Information

System of linear equations:

$3 x + 8 y = - 3 . . . . . . . . . (1) 2 x + 5 y = - 3 . . . . . . . . . (2)$

Step 2. Calculation

Here both equations are in standard form. To get opposite coefficients of y multiply first equation with $- 5$ .

$- 5 (3 x + 8 y) = - 5 (- 3) - 15 x - 40 y = 15 . . . . . . . . . . (3)$

Also multiply second equation with 8.

$8 (2 x + 5 y) = 8 (- 3) 16 x + 40 y = - 24 . . . . . . . . . . (4)$

Solve for x:

From equations $(3)$ and $(4)$ :

$- 15 x - 40 y = 15 16 x + 40 y = - 24 x = - 9 x = - 9$

Solve for y:

Substitute $x = - 9$

in the equation $3 x + 8 y = - 3$ and solve for y.

$3 x + 8 y = - 3 3 (- 9) + 8 y = - 3 - 27 + 8 y = - 3 8 y = 27 - 3 8 y = 24 y = \frac{24}{8} y = 3$

The solution for the system of linear equation is $(- 9, 3)$ .

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In the following exercises, solve the systems of equations by elimination.
$3 x + 8 y = - 3 2 x + 5 y = - 3$

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Calculation

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In the following exercises, solve the systems of equations by elimination.3x+8y=-32x+5y=-3

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Step by step solution

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One App. One Place for Learning.

Most popular questions from this chapter

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In the following exercises, solve the systems of equations by elimination.
$3 x + 8 y = - 3 2 x + 5 y = - 3$