Suppose that the distance, in miles, that people are willing to commute to work is an exponential random variable with a decay parameter 120. Let X = the distance people are willing to commute in miles. What is m, μ, and σ? What is the probability that a person is willing to commute more than 25 miles?

Short Answer

Expert verified

The values of m,μand σare,

m=120

μ=20

σ=20

The value of probability of a person is willing to commute more than 25miles is 0.2865.

Step by step solution

01

Given information

People are willing to commute to work is an exponential random variable with a decay parameter 120

X = the distance people are willing to commute in miles.

02

Solution

The distance in miles is shown to be exponentially distributed with a decay value of 120. It is known that the decay rate (m)is common of mean (μ)for the exponential distribution. So,

m=120

Then,

μ=1m

=11/20

=20

It's also common knowledge that the mean of an exponential distribution equals its standard deviation. Hence,

σ=μ

=20

03

Solution

The exponential distribution's cumulative distribution function is now:

P(X<x)=1emx

As a result, the probability that a person will commute more than 25miles can be computed as follows:

P(x>25)=1P(x<25)

=11e120×25

=e1.25

=0.2865

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