The following data are the shoe sizes of 50male students. The sizes are continuous data since shoe size is measured. Construct a histogram and calculate the width of each bar or class interval. Suppose you choose six bars.

9;9;9.5;9.5;10;10;10;10;10;10;10.5;10.5;10.5;10.5;10.5;10.5;10.5;10.511;11;11;11;11;11;11;11;11;11;11;11;11;11.5;11.5;11.5;11.5;11.5;11.5;11.512;12;12;12;12;12;12;12.5;12.5;12.5;12.5;14

Short Answer

Expert verified

The histogram of the given 50sampled student is

Step by step solution

01

Given

Here we have

9;9;9.5;9.5;10;10;10;10;10;10;10.5;10.5;10.5;10.5;10.5;10.5;10.5;10.511;11;11;11;11;11;11;11;11;11;11;11;11;11.5;11.5;11.5;11.5;11.5;11.5;11.512;12;12;12;12;12;12;12.5;12.5;12.5;12.5;14

02

Explanation

Thedensityofallintervalsisdefinedbythehistogramforeachinterval.
Itindicateswhichintervalshavethelowestfrequencyandwhichhavethehighestfrequency.
Asaresult,wecansimplydeterminethemaximumandlowestshoesizeintervals.
As we can see, the maximum bar height does not equal the highest frequency since bars indicate area.
The interval 11to 12has the highest frequency.

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