Suppose that 20,000 married adults in the United States were randomly surveyed as to the number of children they have. The results are compiled and are used as theoretical probabilities. Let X = the number of children married people have.

a. Find the probability that a married adult has three children.

b. In words, what does the expected value in this example represent?

c. Find the expected value.

d. Is it more likely that a married adult will have two to three children or four to six children? How do you know?

Short Answer

Expert verified

(a) The probability that a married adult has three children.

(b) The expected value represents the average number of children a married people having.

(c) The expected value represents the average number of children a married people having.

(d) It more likely that a married adult will have two to three children.

Step by step solution

01

Given information (part a)

Given the results of a survey conducted on the number of children married adults have.

02

Explanation (part a)

X
PX
0
0.10
1
0.20
2
0.30
3
0.20
4
0.10
5
0.05
6 or more
0.05
Total1

Because the sum of all probabilities for a random variable is 1, the probability x=3 equals 1-sum of all probabilities.

03

Given information (part b)

Given the results of a survey conducted on the number of children married adults have.

04

Explanation (part b)

The expected value in the scenario in question represents the average number of children a married couple has.

05

Given information (part c)

Given the results of a survey conducted on the number of children married adults have.

06

Explanation (part c)

X
PX
X.Px
0
0.10
0
1
0.20
0.20
2
0.30
0.60
3
0.20
0.60
4
0.10
0.40
5
0.05
0.25
6 or more
0.05
0.30
Total1
2.35

Ex=x.PxEx=2.35

07

Given information (part d)

Given the results of a survey conducted on the number of children married adults have.

08

Explanation (part d)

A married adult with two to three children is more likely to have two to three children than a married adult with four to six children because the likelihood of having two to three children is greater than the probability of having four to six children. A person's chances of having two to three children are 0.50, while his or her chances of having four to six children are 0.20.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In words, the random variableX=_________________

a. the number of times Mrs. Plum’s cats wake her up each week.

b. the number of times Mrs. Plum’s cats wake her up each hour.

c. the number of times Mrs. Plum’s cats wake her up each night.

d. the number of times Mrs. Plum’s cats wake her up.

On May 11, 2013 at 9:30 PM, the probability that moderate seismic activity (one moderate earthquake) would occur in the next 48hours in Japan was about 1.08%. As in Example 4.8, you bet that a moderate earthquake will occur in Japan during this period. If you win the bet, you win \(100. If you lose the bet, you pay\)10. Let X = the amount of profit from a bet. Find the mean and standard deviation of X.

You are playing a game of chance in which four cards are drawn from a standard deck of 52 cards. You guess the suit of each card before it is drawn. The cards are replaced in the deck on each draw. You pay \(1 to play. If you guess the right suit every time, you get your money back and \)256. What is your expected profit of playing the game over the long term?

A palette has 200 milk cartons. Of the 200 cartons, it is known that ten of them have leaked and cannot be sold. A stock clerk randomly chooses 18 for inspection. He wants to know the probability that among the 18, no more than two are leaking. Give five reasons why this is a hypergeometric problem.

There are two similar games played for Chinese New Year and Vietnamese New Year. In the Chinese version, fair dice with numbers 1, 2, 3, 4, 5, and 6 are used, along with a board with those numbers. In the Vietnamese version, fair dice with pictures of a gourd, fish, rooster, crab, crayfish, and deer are used. The board has those six objects on it, also. We will play with bets being \(1. The player places a bet on a number or object. The “house” rolls three dice. If none of the dice show the number or object that was bet, the house keeps the \)1 bet. If one of the dice shows the number or object bet (and the other two do not show it), the player gets back his or her \(1 bet, plus \)1 profit. If two of the dice show the number or object bet (and the third die does not show it), the player gets back his or her \(1 bet, plus \)2 profit. If all three dice show the number or object bet, the player gets back his or her \(1 bet, plus \)3 profit. Let X = number of matches and Y = profit per game.

a. In words, define the random variable X.

b. List the values that X may take on.

c. Give the distribution of X. X ~ _____(_____,_____)

d. List the values that Y may take on. Then, construct one PDF table that includes both X and Y and their probabilities.

e. Calculate the average expected matches over the long run of playing this game for the player.

f. Calculate the average expected earnings over the long run of playing this game for the player

g. Determine who has the advantage, the player or the house.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free