A grassroots group opposed to a proposed increase in the gas tax claimed that the increase would hurt working-class people the most, since they commute the farthest to work. Suppose that the group randomly surveyed 24individuals and asked them their daily one-way commuting mileage. The results are in Table 13.22. Using a 5%significance level, test the hypothesis that the three mean commuting mileages are the same.

Short Answer

Expert verified

We accept the null hypothesis.

Step by step solution

01

Given Information

A grassroots group opposed to a proposed increase in the gas tax claimed that the increase would hurt working-class people the most, since they commute the farthest to work. Suppose that the group randomly surveyed 24individuals and asked them their daily one-way commuting mileage.

02

Use Ti-83 calculator 

Consider the null hypothesis that there is no significance difference between three mean commuting mileages. To test the mean commuting mileage are same at 5%level of significance, use Ti-83 calculator. For this, click on STAT press 1EDIT, then put the above given weights of different groups data into the list L1,L2,andL3. The screenshot is given as below.

03

Explanation

Now Again press STAT arrow over the TESTS localid="1649235797890" arrow down to ANOVA localid="1649239023592" Press var then select1, press var then select 2 , and press var then select 3 to fill the values of localid="1649235791952" L1,L2,andL3. The screen shot is given as below:

04

Explanation

Press ENTER. The screenshot of the obtained output of is given as below:

05

Hypothesis test

Use the above results to solve the below given subparts.

The null hypothesis that three mean commuting mileages are same is given as below:

H0:μ1=μ2=μ3

The alternate hypothesis will be at least any two of the means are different.

The degree of freedom in the numerator is 2, and the degree of freedom in the denominator is 21.

The Fdistribution is used for the test of three different means.

The value of the test statistic is 9.09.

06

Explanation

The P-value for the test is 0.001.

The graph of the distribution is given as below:

07

Explanation

Level of significance αis 0.05.

Decision: Null hypothesis will be rejected.

Reason for decision: P-value is 0.001which is less than the 0.05level of significance.

Three mean commuting mileages are not same.

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