Refer to Exercise 9.119. Conduct a hypothesis test to see if your decision and conclusion would change if your belief were that the brown trout's mean I.Q is not four.

Short Answer

Expert verified

The brown trout's mean I.Q is not four.

Step by step solution

01

Introduction

Null hypotheses is,

H0:μ=4

Alternative hypotheses is,

H0:μ4

The random variable X¯ is the averageI.Q.

n-1=11

Sample mean is,

x¯=5+4++8+512

=4.92

Sample standard deviation is,

s=j=1nxj-x¯2n-1

=j=112xj-4.92211

=1.62

Test is,

t11=4.92-41.62/12

=1.958

02

Explanation

We do not reject the null hypothesis when the pvalue is bigger than the established alpha value.

p-value=0.076>0.05

=α

Mean and variance of random is,

x¯-tα2,n-1snμx¯+tα2,n-1sn......1

where tα2,n-1is the upper

100α2percentage point of the distribution with n-1degrees of freedom.

α2=0.025

ta2,n-1=t0.025,11

=2.2.......2

From 1and2,

4.92-2.21.6212μ4.92+2.21.6212

4.92-2.2×0.468μ4.92+2.2×0.468

Population proportion is,

3.886μ5.947

Therefore, Mean I.Q is not four (4).

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