You flip a coin and record whether it shows heads or tails. You know the probability of getting heads is 50%, but you

think it is less for this particular coin. What type of test would you use?

Short Answer

Expert verified

A left-tailed test is used in this scenario.

Step by step solution

01

Introduction

The rejection zone in left-tailed test is at the extreme left of the distribution. The null hypothesis in this case is that the claimed value is less than or equal to the population mean value.

02

Explanation

As the alternative hypothesis asserts that the likelihood of getting a heads is less than 0.5, a left-tailed test is required. For better understanding, the null and alternative hypotheses should always be written.

A diagram depicting a left-tailed test.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Sixty-eight percent of online courses taught at community colleges nationwide were taught by full-time faculty. To test if 68% also represents California’s percent for full-time faculty teaching the online classes, Long Beach City College (LBCC) in California, was randomly selected for comparison. In the same year, 34 of the 44 online courses LBCC offered were taught by full-time faculty. Conduct a hypothesis test to determine if 68% represents California. NOTE: For more accurate results, use more California community colleges and this past year's data.

A statistics instructor believes that fewer than 20% of Evergreen Valley College (EVC) students attended the opening night midnight showing of the latest Harry Potter movie. She surveys 84of her students and finds that11of them attended the midnight showing.

At a1% level of significance, an appropriate conclusion is:

a. There is insufficient evidence to conclude that the percent of EVC students who attended the midnight showing of Harry Potter is less than20%.

b. There is sufficient evidence to conclude that the percent of EVC students who attended the midnight showing of Harry Potter is more than 20%.

c. There is sufficient evidence to conclude that the percent of EVC students who attended the midnight showing of Harry Potter is less than20%.

d. There is insufficient evidence to conclude that the percent of EVC students who attended the midnight showing of Harry Potter is at least 20%

Your statistics instructor claims that 60percent of the students who take her Elementary Statistics class go through life feeling more enriched. For some reason that she can't quite figure out, most people don't believe her. You decide to check this out on your own. You randomly survey 64of her past Elementary Statistics students and find that 34feel more enriched as a result of her class. Now, what do you think?

The student academic group on a college campus claims that freshman students study at least 2.5 hours per day, on average. One Introduction to Statistics class was skeptical. The class took a random sample of 30 freshman students and found a mean study time of 137 minutes with a standard deviation of 45 minutes. At α=0.01 level, is the student academic group’s claim correct?

A sociologist claims the probability that a person picked at random in Times Square in New York City is visiting the area is0.83You want to test to see if the claim is correct. State the null and that alternative hypothesis.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free