The cost of a daily newspaper varies from city to city. However, the variation among prices remains steady with a

standard deviation of 20¢. A study was done to test the claim that the mean cost of a daily newspaper is $1.00. Twelve costs

yield a mean cost of 95¢ with a standard deviation of 18¢. Do the data support the claim at the 1% level?

Short Answer

Expert verified

The data support the claim that the mean cost of a daily news paper is $1.00

Step by step solution

01

Given Information

Given

the sample size n=12

Twelve costs yield a mean cost of $0.95with a standard deviation of $0.18

mean of the samplelocalid="1650204298826" (x)=$0.95

Standard deviation of sample (S)=$0.18

Given claim that the mean cost of a daily newspaper is $1.00.

The mean of the population 'μ'=$1.00.

Null hypothesis:-H:'μ'=$1.00.

Alternative hypothesis:H:'μ'$1.00.

level of significance=0.01

02

Explanation

The test statistic on calculation, we get

t=-0.96

|t|=|-0.96|=0.96

Degrees of freedomγ=n-1=12-1=11

t=2.718

Calculated value t=0.96

Tabulated value t=0.01level for 11°for two tailed test = 2.718

since calculated' t' value is less than tabulated value 't'.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

H0:μ1,Ha:μ>1

Assume the p-value is 0.1243. What type of test is this? Draw the picture of the p-value.

Toastmasters International cites a report by Gallop Poll that 40% of Americans fear public speaking. A student believes that less than 40% of students at her school fear public speaking. She randomly surveys361 schoolmates and finds that135 report they fear public speaking. Conduct a hypothesis test to determine if the percent at her school is less than 40%.

A bathroom scale claims to be able to identify correctly any weight within a pound. You think that it cannot be that

accurate. What type of test would you use?

It’s a Boy Genetics Labs claim their procedures improve the chances of a boy being born. The results for a test of a single population proportion are as follows:

H0:p=0.50,Ha:p>0.50

α=0.01

p-value=0.025.

Interpret the results and state a conclusion in simple, non-technical terms.

A statistics instructor believes that fewer than 20% of Evergreen Valley College (EVC) students attended the opening night midnight showing of the latest Harry Potter movie. She surveys 84 of her students and finds that 11 of them attended the midnight showing. At a 1% level of significance, an appropriate conclusion is:

a. There is insufficient evidence to conclude that the percent of EVC students who attended the midnight showing of Harry Potter is less than 20%.

b. There is sufficient evidence to conclude that the percent of EVC students who attended the midnight showing of Harry Potter is more than 20%.

c. There is sufficient evidence to conclude that the percent of EVC students who attended the midnight showing of Harry Potter is less than 20%.

d. There is insufficient evidence to conclude that the percent of EVC students who attended the midnight showing of Harry Potter is at least 20%.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free