84. Repeat the test in Exercise 10.83, but use Lap 5 this data.

Short Answer

Expert verified

(a) The null hypothesis:H0:μ1=μ2
(b) The alternate hypothesis: Ha:μ1μ2
(c) The difference between the mean times for completing a lap in races and in practices is denotes by X1¯-X2¯.
(d) Student's t distribution
(e) The test statistic: -3.3065
(f) The p-value: 0.00138

(g) Check student's solution:
(h)(i) α=0.05

(ii) Decision: Reject the null hypothesis.

(iii) Reason for Decision: α>p-value.

(iv) Conclusion: There is sufficient evidence to conclude that the mean time for completing a lap in races is different from that in practices, at the 5%significance level

Step by step solution

01

Given information

To repeat the test in Exercise 10.83, but use Lap 5this data.

02

Explanation

(a) The null hypothesis is indicated as follows:
H0:μ1=μ2
(b) The alternate hypothesis is indicated as follows:
Ha:μ1μ2
(c) The variation between the mean times for finishing a lap in races and practices is denoted by is denotes by X1¯-X2¯.
(d) Student's t distribution.

(e) For the mean difference, the paired test static as follows:

Then ENTER all values the OUTPUT will look like this:

Hence, the test statistics is -3.3065.

03

Explanation

(f) The p-value from the output is 0.00138.
(g) Using the data from the last exercise, create a mental picture of the situation.
The horizontal axis should be clearly labelled and scaled, and the p-value-corresponding region(s) on the graph should be shaded.

(h)

(i) α=0.05
(ii) Decision: Null hypothesis is rejected.
(iii) α>p-value
(iv) Conclusion: There is enough evidence to conclude that the mean time for completing a lap in races is different from that in practices, at the 5%significance level.

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