A local cancer support group believes that the estimate for new female breast cancer cases in the south is higher in 2013 than in 2012. The group compared the estimates of new female breast cancer cases by southern state in 2012 and in 2013. The results are in Table 10.32.

The given data is

We have to solve the problem by using this data.

a. the null hypothesis is

${\mu }_d=0$

b. The alternative hypothesis is,

${\mu }_d\ne 0$

c. The mean of new female breast cancer cases in the south between 2013 and 2012 is greater than zero. In 2013, the number of new female breast cancer cases in the South is expected to be higher than in 2012.

d. The t distribution of a student.

e. Fill in all requirements using Minitab's two sample t-test option.

The result shown below

Test statistic is$4.40$

f. The P value is $0.00$

g.The graph is not created since the P value is zero.

i. $\alpha =0.05$

ii. Conclusion: the null hypothesis must be rejected.

p value is the reason for the decision.$Pvalue>\alpha$

iv. Conclusion: At the $5\%$level of significance, there is adequate evidence from the sample data to indicate that the number of new female breast cancer cases in 2013 was greater than in 2012.