Explanations 
Textbooks 
Exams 
GCSE 
IGCSE 
AS 
A Level 
International A Level 
University Admissions Tests 
Flashcards 
Vaia AI 
Notes 
Study Plans 
Study Sets 
Find a job 
Find a degree 
Student Deals 
Magazine 
Mobile App Chapter 12: Q. 50 (page 719)
Find the correlation coefficient.
a. correlation = _____
Short Answer
Expert verified
\(r=0.45\)
Step by step solution
01
Step 1. Given information
Given,
02
Step 2. Calculation
\(r=\frac{N\sum xy-(\sum x)(\sum y)}{\sqrt{[N\sum x^{2}-(\sum x)^{2}][N\sum y^{2}-(\sum y)^{2}]}}\)
\(r=\frac{22\times 1598786198-(43813)(802027)}{\sqrt{[22(87254475)-43813^{2}][22(42471498895)-802027^{2}]}}\)
\(r=\frac{34087405}{75308824.97}\)
\(r=0.45\)
We have given the data of years and no. of flu cases diagnosedusing that data we calculated few statistics then putting all those statistics in the formula of correlation coefficient then we have got the value of \(r\).
The correlation coefficient of the given data is equal to \(0.45\).
Over 30 million students worldwide already upgrade their learning with Vaia!
