Use the following information to answer the next two exercises. This tree diagram shows the tossing of an unfair coin followed by drawing one bead from a cup containing three red(R),four yellow(Y)and five blue(B)beads. For the coin, andP(H)=23andP(T)=13whereHis heads andTis tails .

Find P(Blue bead).

a.1536

b.1036

c.1012

d.636

Short Answer

Expert verified

Possibility of five blue bead is1012,So answer c is correct.

Step by step solution

01

Given data

From tree diagram,

Probability of tossing Head on the coin is P(H)=23.

Probability of tossing Tail on the coin is P(T)=13.

Probability of tossing head on the coin with five blue beads is P(B|H)=512.

Probability of tossing tail on the coin with five blue beads isP(B|T)=512

02

Calculation for possibility of five blue beads

Possibility is,

P(Bluebead)

=P(Bluebead|tossingaHeadoncoil)+P(Bluebead|tossingatailoncoil)

=P(B|H)+P(B|T)

=512+512

=1012

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